(i)Magnitude shud be -ve otherwise the body can't be in equilibrium
and Vρg = qE
(ii) Now when it captures two electrons..net force on it
=(q+2e)E - Vρg
Tanmoy Das Thank you!!!
Upvote·0· Reply ·2014-04-16 09:46:43
A charged drop of oil of radius 2.76μm and density 920kg/m3 is held stationary in a vertically downward electric field of 1.65*106N/C.(i).Find the magnitude and sign of the charge on the drop.(ii) If the drop captures two electrons in the same electric field, what would be its acceleration? Ignore viscous drag.
(i)Magnitude shud be -ve otherwise the body can't be in equilibrium
and Vρg = qE
(ii) Now when it captures two electrons..net force on it
=(q+2e)E - Vρg