electroooostatics...small dbt

BITSAT 2015 Papers › Electricity and magnetism questions › electroooostatics...small dbt

a large sheet carries uniform surface charge density sigma and a rod of length 2l has a linear charge density lambda on 1 half and -lambda on other half the rod is hinged at midpoint O and makes an angle theta with the normal to the sheet....the torque experienced by the rod is....

#Physics #Electricity and magnetism

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6 Answers

1

AARTHI ·2009-04-02 07:38:32

ans is Î» Ïƒ l²sinÎ¸/2Îµ

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1

Optimus Prime ·2009-04-02 09:09:16

\lambda \sigma l^{2}sin\theta /2\varepsilon

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33

Abhishek Priyam ·2009-04-02 11:35:44

force on elementary length. = EÎ»dx
torque=EÎ»dxxsinÎ¸

integrating from 0 to l we get Î»EsinÎ¸l²/2

similarly for lower part (-Î»)
torque in same sense. Î»EsinÎ¸l²/2

so net torque = Î»EsinÎ¸l²
E=Ïƒ/2Îµ₀

so Ï„= Î»EsinÎ¸l²/2Îµ₀

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33

Abhishek Priyam ·2009-04-02 11:37:16

as force in constant so u could have used (Î»l)EsinÎ¸(l/2) for torque on upper part ...(force on center of rod. at l/2)

similarly for lower part.

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AARTHI ·2009-04-02 11:54:39

tx priyam ....[1]

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Abhishek Priyam ·2009-04-02 11:56:58

:)

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω