Electrostatic-1

One or more than one may be correct.

1 Answers

1057

Ketan Chandak ·2013-02-20 22:54:59

kq_A/R+kq_B/2R=2V ...(1)

kq_A/2R+kq_B/2R=(3/2)V

Solving the equations,
q_A/q_B=1/2.

After B is earthed,potential of B becomes zero.
V_a=V_c and V_a>V_b
q^'_B=-q^'_A=-q_A
or q^'_A/q^'_B=-1

V_a-V_b=kq_A/2R
Substituting q_B=2q_A,we get kq_A/2R=V/2
V_A-V_B=V/2
V_B=0 since V_A=V/2.

hence,correct options are a,d.

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