24haan priyam.[4][4]..........mera bhi aa gaya tha raat ko[3][3]...............main to mathie ko chaalenge kar raha thaa ki meri galti nikale[6]..............mujhe mere answers par pura bharosa hai .....hamesha......[1]
if u know this it is easy but if u dont know, its worth knowing....
Q) a spherical ball of radius R is uniformly charged with charge density Ï .determine the electrostatic energy of the sphere.
-
UP 0 DOWN 0 0 24
24 Answers
24
33are eureka...
u are right... apne par bharosa rakh...
put Ï=Q/(4piR3/3)
aa jaega... kyunki method sahi hai...
and mathiee.. u asked in terms of Ï so should have given answer in its term..
24arre yaar..........tum log hc verma ke peeche pade ho........mere method mein galti batao.....
24hc verma ki ebook nahin milti yaar....mere paas sachi mein hc verma nahin hai...........
1arey e buk dhundle :P
waise bhi etre yahn koi tym pass ke liye kuch ni hai xcept 4 pool :P
39chall hcverma ka gauss law wala topic dekh, udhar se diya hain e wala.
24Good prblem[1]
Usphere=Interaction energy+Self energy
Here we consider a ring of radius r and width dr , so Self energy associated with it can be neglected.
=> dU=VsdQ
Here Vs =(4/3 Ï€r3Ï)/4πεr =Ïr/3ε
and dQ=ÏdV=Ï(4Ï€r2dr)
=>dU=4Ï€/3ε Ï2r4dr
Integrating with limits 0 to R
=>U=4Ï€Ï2/3ε R5/5
1haan ni karnege mein kuch aur soch ri thi sorry
here d sol
energy=Vdq
=(4/3 Πx3)(4Πx2σdx)
isse int karne se m gettin
(3/20q^2)/ΠεR
24tere ans mein Ï ka term kyun nahin hai????????mujhe to mera soln theek lagta hai...
24hey mathie...........reply to kar diya kar.........bata ye theek hai naa???????[12][12]