661. \dfrac{q}{4\pi\epsilon_0r}
It is neutral conductor.
1) Determine the potential of the conductor
2) Determine the potential at A, B and C due to induced charges.
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6 Answers
66The conductor being equipotential, the net potential at A = \dfrac{q}{4\pi\epsilon_0r}.
Also total potential at A = potential at due to q + potential at A due to the induced charges.
Hence, potential due to induced charges = total potential - potential due to q
= \dfrac{q}{4\pi\epsilon_0r} -\dfrac{q}{4\pi\epsilon_0\sqrt{r^2+R^2}}
Similarly for B and C