emi- logical q

a long horizontal metallic rod with length along the east-west direction is falling under gravity.
The potential difference b#w it's 2 ends will

a] increase with time
b]0
c]constant
d]decrease with time

32 Answers

1
skygirl ·

hey ow no change of flux [12]

i thnk i didn get the diagram itself..

1
skygirl ·

arey its moving towards the surface of the earth only...

ab yeh movie nahi hai naa sankara.. :(
(nishant bhiaya din kp dat facility :( )

so the picture is at some instant :P

3
msp ·

hey sky the rod is falling under gravity so it shud moves toward the surface of the earth

1
greatvishal swami ·

bhai how is bB parallel to V

1
greatvishal swami ·

ya i m considering that mathie

but B is const but xarea sweeped is changing so smf inc

........ but still i will recheak it through some book

1
greatvishal swami ·

rod ka area is its length * x( length covered )

we did this whi;le deriving the formula

39
Dr.House ·

ya vishal, i have given correct explanation above, see to it. if we r answering this without considering earth magnetic field, then its wrong.

1
greatvishal swami ·

.magnetic field to hamesha downward hi act karti hai naa....

i think this is not correct eureka

as area sweeped is increasing so induced emf should increase
so ans shud b a)

1
skygirl ·

arey i told A so i will gv explanation for A only naa ... [3]

waise C kyun hai.. mujhe pata nahi...

philip ko bhi A hi mila..

11
Subash ·

sky ans a ka explanation u have given

but mathie says ans is c

i just want to make sure it is a

1
skygirl ·

11
Subash ·

can some one explain this one??

1
skygirl ·

heheh [9] [9]

carried away ??

[9] [9] [9] [9] [9] [9] [9] [9] [9] [9] [9] [9] [9] [9] [9]

1
Philip Calvert ·

sorry i was carried away....

wats the prob u know na answer is A
and it is A so cheer'ap

1
skygirl ·

kya yaar philip.....

first u told C then A...

[12]

[2] [2] [2] [2]

1
Philip Calvert ·

yes !! answer is A then

1
skygirl ·

a hai kya ??

11
Subash ·

I got the same doubt as philip

but then answer would be a because velocity is increasing due to the fall

mathie im not getting ur explanation what about motional emf then??

1
Philip Calvert ·

read it two more times b5555 but i cant see any change at any time.....
it was initially the same with me..

but plz could you see that Motional emf in HC verma once again

I'll do that too..
i feel there's the best explanation regarding accumulation of charges...

you can derive that Blv thing on your own just equate force due to induced electric field and force due to magnetic field..

but yes lets go thru HC verma once again...

39
Dr.House ·

yaar, the above was the best explanation i could give, read it one more time.

1
Philip Calvert ·

[7][7][7][7][7][7][7][7][7][7][7][7][7][7][7][7]
[7][7][7][7][7][7][7][7][7][7][7][7][7][7][7][7]
[7][7][7][7][7][7][7][7][7][7][7][7][7][7][7][7]

what was that??

hey b5555 can you explain just a bit more...

i solved atleast 200 questions in which B was uniform and the rod moving with constant speed v(_|_ to B) and pot. diff (in this case motional emf) was in all cases was "BLv"

can you explain how is this case diff....

answer is C no doubt about that...

1
Akand ·

hehe thts y i had a doubt......................

39
Dr.House ·

akand u r rite its constant

sorry aaj thoda dimaag kaam nahiin kar raha, chalo here goes my explanation

The earth's magnetic field has a role to play here. Now, the length of the rod is in the east-west direction and it is falling vertically under the action of gravity. So, the component of the earth's magnetic field which is perpendicular to the velocity of the rod as well as the length of the rod i.e in the north-south direction, should be taken into consideration.

But here the earth's manetic field along the north-south direction, is constant in magnitude and continous throughout the space i.e there is no change of flux linked with the freely falling rod.

Now, the induced emf = - rate of change of flux w.r.t time = 0
(since, the flux linked with the rod remains constant)

Hence, the potential difference, across the ends of the rod is 0

39
Dr.House ·

JO HOTA HAI ACCHE KE LIYE HOTA HAI
GOIN BAD IS NOT GOOD BUT HAVIN BAD IS GOOD ALWAYZ AT THE END........................................................

1
Akand ·

plzzzzzzzz explain mathi.........

39
Dr.House ·

answer is d

1
skygirl ·

but B is increasing !!

1
skygirl ·

of crz it has got to do.....

koi toh mag field hoga.. jab koi nahi hai toh ... nature is always there :)

1
Akand ·

since its always perpendicular to it............so it will be constant rite??

1
skygirl ·

:P

ans a hai kya ?

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