fjee capacitors-------

the battery of volatge V=10 V .. three capacitors each of 3μF and 5 resistors each of 1Ω are aranged as shown in the fig.

arrangement is left for long time so that steady state is reached.

then:

1) charge on cap 1

2) charge on cap 2

3) charge on cap 3

4) voltage drop across cap 3.

33 Answers

1
prateek punj ·

yaar koi complete solution de sakta hai....

1
skygirl ·

my doubt is more stupid: y current flows through red wire only ?

1
Pavithra Ramamoorthy ·

i think due to dc source....

more stupid ans???????????

no current thro capacitor....

13
Двҥїяuρ now in medical c ·

capacitor blocks current...DC to be specific

11
Subash ·

steady state sky infinite resistance for capacitor

1
skygirl ·

ok....... yeh achha rep tha.... thanx ..

11
Subash ·

rep??

1
Pavithra Ramamoorthy ·

represtation,

reproduction,

repetition,

..

choose d best which matches.....

1
Philip Calvert ·

reply

33
Abhishek Priyam ·

current flows in red wire i=10/3

V across C2 =iR =10/3
q=CV =10/3*3=10

V across C1=10
q=3.10=30

V across C3=10-iR=20/3
q=cV=20

1
skygirl ·

uff it is reply :P :P :P

1
Pavithra Ramamoorthy ·

priyam ka post nahi dhaeka??????????? #18

@prateek

1
kamalendu ghosh ·

1
skygirl ·

heheh... :D

etar theke toh question er circuit ta easy laglo :P

sorry... but ... :'(

1
kamalendu ghosh ·

1
kamalendu ghosh ·

1
skygirl ·

wowwwwwwwwwww!! ki rakom bachchader mato bojhali :P

but ... thanx ......

1
king_khan ·

Ans :

1 ) Cap1 : 30 μF

2) Cap2 : 10 μF

3) Cap3 : 20 μF

4) 20/3 V

Correct hai ????

33
Abhishek Priyam ·

1
Pavithra Ramamoorthy ·

hey .. sky.. waiting fr u fr a lon time........

do u ve d sol fr dis?????????

is kingh kahn rit?????(#2)

1
skygirl ·

please ..............

i need some good explanation....

@nishant bhaiya or manish bhaiya or kaymant sir ...

can i have any one of yours' replies....

any ''confident'' replies from students will also do...

1
Pavithra Ramamoorthy ·

teek.......... ab mujhe chod dho.....

i ll try it later.....

really not in a state to solve dis.... ma eyes r droopin..

1
°ღ•๓яυΠ·

kisne kahah yeh arey ni u make diagrm n c itz nt same

only d currnt tru caps is zero n it acts like open circuit in

1
Pavithra Ramamoorthy ·

v is same at any point in d circuit?????????/

makin a mistake here...........

1
°ღ•๓яυΠ·

arey c jsut chnge d cube type structure into a flat one itz easy

1
°ღ•๓яυΠ·

take it as say V1 nw d currnt wich will pass thru will b same so get an equaktion in V and V1 R is 1 u noe so u get V1 a s 10/3

then for d first one itz simply (10-0)3

for second u get (20/3 -10/3) 3

for d third one u get
10-10/3 into 3

i mean apply loop law

1
Pavithra Ramamoorthy ·

dats wat i m askin frm d beginnin......... i kno its easy after findin v.......

but how do u find v ?????????

1
°ღ•๓яυΠ·

u find d volatge drop u get V as 10/3
so nw d drop across d 2 cap is 20/3 so chrge is 20

:)

1
Pavithra Ramamoorthy ·

@sri..wat do u say now???/ flaw in d q???????

i think theres some trick dat we don get it........... srry not we , i

1
sriraghav ·

@sky....There r two unneccessary wires conncting (note the sides of cuboid )...If u remove them and drw , i will b a simple linear circuit.......I think king is rite.....

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