1how ?
i did flux[curve]= q/E - flux thru 2 circles
flux thru 2 circles=q/2E[1-4/5], q/2E[1-12/13]....got this by integrating..
now subtract--- u get 56/65.,
value of [flux]*[epsilon] through curved surface=?..
i'm getting 56/65..
pls confrm...
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6 Answers
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1Yep , I did a silly mistake . Your answer is absolutely correct . However , there is no need of doing painful integrations if you know the concept of Solid Angle .
1i don't know much abt solid angle....how does dat helpt here? pls tell[in short]
thanks
1I have CBSE AISSCE Mathematics exam tomorrow : ) I ' ll start a long thread on the ways of calculating flux and about solid angles tomorrow only , okay ? Please wait for a day : )