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my doubt since ∫dl=0 why net force is not 0?

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62
Lokesh Verma ·

why is ∫dl = 0 ??

infact that is 2Ï€R (if your direction is along the loop)

∫dx over the loop is zero
∫dy over the loop is zero
but ∫√dx2+dy2 over the loop is not zero

and net force is not zero.. because the force is a vector.. and one component of the force are not distributed such that the forces cancel each other...

1
Kaustab Sarkar ·

ok thanks :)

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