one more..plzzz help me......

An electron falls through a distance of 1.5 cm in a uniform electric field of magnitude 2.0\times 10^{4}NC^{-1}. The direction of the field is reversed keeping its magnitude unchanged and a proton falls through the same distance.Compute the time of fall in each case.Constrast the situation with that of free fall under gravity.

4 Answers

1
hirok ·

draw the graph of y=10x ?

1
Arka Halder ·

1.we can calculate the force acting on the particle(electron and proton) in each case..F=qE.
acceleration a in each case a=F/m..
then from relation S=at2/2,we get the time taken.
the case will be similar as that of free fall under gravity,the only difference being that the time of fall is independent of mass in case of free fall under gravity,whereas in this case the acceleration and thus the time of fall will depend on the charge of the particle.

1
Arka Halder ·

2.
Should be like this somewhat..

1
Arka Halder ·

for x<0,10x will be less than 1.
for greater values it will keep on increasing.
thus we get a curve as shown above.

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