1u r right priyam
two particles x n y of equal mass an unequal positive charge are free to move and are initially far away .With y at rest x begins to move towards it with inital velocity u .after long time
(A)x ll stop n y ll move with velocity u
(B)x n y both ll move with velocity u/2
(C)x ll stop n y ll move wid velocity <u/2
(D)both move wid velocity<u/2
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3 Answers
33u1.u2=0
because after long time potential energy will be zero...(min possible..)
By momentum consrevation..
u1+u2=u
1/2mu2=1/2m(u12+u22)
u2=(u1+u2)2-2u1u2
u1u2=0
either of the two will become zero...
So only option is (a) with u1=0