pls solve

VITEEE 2015 Questions › Electricity and magnetism questions › pls solve

#Physics #Electricity and magnetism

UP 0 DOWN 0 1 27
Post on FacebookPost anonymously?

27 Answers

11

Mani Pal Singh ·2009-02-23 07:26:32

i know
yr 2nd ans is also correct
pls post the soln

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-25 09:54:55

mere ko ab tum bevakoof mat samjho !!!!!!!!!!!
give me proper explainations

UP 0 DOWN 0
Post on FacebookPost anonymously?

39

Dr.House ·2009-02-25 09:51:23

iii) a,b,cd aa raha hain. woh last wala dekhna hain........

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-25 09:51:01

how??????

UP 0 DOWN 0
Post on FacebookPost anonymously?

106

Asish Mahapatra ·2009-02-25 09:46:50

(iv) - (b)

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-25 09:43:12

baaki 3

UP 0 DOWN 0
Post on FacebookPost anonymously?

39

Dr.House ·2009-02-25 09:40:59

A toh aaa raha hain

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-25 09:37:58

YAAR DHYAAN SE DEKH ANS IS WRITTEN
ITS C AND A

UP 0 DOWN 0
Post on FacebookPost anonymously?

106

Asish Mahapatra ·2009-02-25 09:34:04

Q2. (ii) - (c)(a).... if voltmeter is attached in series then it has infinite resistance hence no current flows... but i dont know abt charge on capacitor maybe mathie can help... ya ya voltmeter reading will be 2V as well... uska jo side cell ke taraf hai us par potenial is 2V aur doosre taraf potential is 0V ... That's why no charge is developed on capacitor as well. as there is no pot. diff. across any end... both ends are at pot. zero.

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-25 02:40:00

sir ek baar isko bhi dekh lo

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-25 01:08:08

yaar apna ans to post kar de

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 20:09:47

mr iit please give the soln
ur ans is correct

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 08:51:07

ashish actually sara Q2 ek match matrix hai
give ur ans i will let u know later

UP 0 DOWN 0
Post on FacebookPost anonymously?

106

Asish Mahapatra ·2009-02-23 08:49:01

manipal wat is answer of Q2b part iii?

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 03:55:46

UP 0 DOWN 0
Post on FacebookPost anonymously?

3

iitimcomin ·2009-02-23 07:25:03

rest of it is beyod my syllabus!!!!!

UP 0 DOWN 0
Post on FacebookPost anonymously?

3

iitimcomin ·2009-02-23 07:24:32

2. im gettin 3.5 as answer is it correct????

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 07:08:32

oh i misunderstood it

thanks

UP 0 DOWN 0
Post on FacebookPost anonymously?

3

iitimcomin ·2009-02-23 07:07:03

to be presice 1.2909944487358697

UP 0 DOWN 0
Post on FacebookPost anonymously?

3

iitimcomin ·2009-02-23 07:05:15

yep my answer is root(5/3) = 1.29 !!!!!!

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 06:46:50

vaise gud try
+2 students

WAKE UP

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 06:41:27

sorry but ans is 1.28

UP 0 DOWN 0
Post on FacebookPost anonymously?

3

iitimcomin ·2009-02-23 06:41:07

loop is fixed toh my ans. is rite otherwise its not!!!!!!

UP 0 DOWN 0
Post on FacebookPost anonymously?

3

iitimcomin ·2009-02-23 06:39:24

prob no 3 ... at the topmost point if the net force is just zero it will complete the circle.....

or in other words mv²/2 = mg ............

or v= âˆš2g ......(1) .........

conserving energy .......

1/2m(2g) + mg(4) = 1/2 mu² .....

10mg = mu² .........

u = âˆš10g!!!!!

again 1/2mu² = 1/2(k)x²...........

(10)mg = 3x² ....
âˆš5/3=x .... pardon calc. mistakes[1]

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 06:30:52

35 baande online and no attempts
please help
it will definitely help in jee

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 03:59:10

UP 0 DOWN 0
Post on FacebookPost anonymously?

11

Mani Pal Singh ·2009-02-23 03:57:11

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω