plz help!!!!!!!!!!!!!!!

A charge of 200 μC is imparted to each of the 2 identical parallel plate capacitor connected in parallel. At t=0, the plates of both capacitors are placed 1 m apart. The paltes of 1st capacitor moves towards each other with relative velocity = 0.001 m/s and the plates of 2nd capacitor moves apart with same relative velocity. Find the currecnt in the circuit at the moment.

4 Answers

1
Anurag Khandelwal ·

Current= dq/dt
q=CV, V is constant; C=EA/x;
dq/dt= V(dC/dt)
C=C1+C2
dC/dt=dC1/dt+dC2/dt
=-EA/xi2(v1+v2)

Substitute, xi=1m, v1=0.001 and v2=0.001

i= 2*C*V*v/xi
= 2*qi*v/xi
=2*200*0.001/1
=4??

1
Surbhi Agrawal ·

ans given is 2μA.

1
Anurag Khandelwal ·

I'm sorry, the sum of v1 and v2 will not b zero.... i'm editing my earlier post...

1
Surbhi Agrawal ·

ohk!!!![1]

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