1man , I think the reverse bias current should be 50μA not 50mA . please check.
diode and ressitor are connected to 2volt ,I=20mA,then it is reversed I=50mA,what is forward resistance of diode and resistor ,give me hint
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7 Answers
1sir ur method seems to be wrong,neither the forward nor the backward resistance is zero and it is not mentioned either it is parallel or series
62i think i was wrong
i shot off too fast on this one...
actually i think now that they will be in parallel :D
sorry for confusing all of ur...
62v=iR will give the rresistance of the resitor when it is backward biased (assuming very high resistance of the diode!)
so R=2/50mA = 2000/50 = 40 ohms...
when forward biased,
effective resistance is 50R/(50+R)
2=20. 50R/(50+R)
1/500=R/(50+R)
50+R=500R
R=1/10 ohms..
now i hope this is correct :)
162that is what .. you have to first justify that it is in parallel..
cos in series.. the diode becomes very large resistor.. so the current would have fallen by a huge quantity..