C-10

JEE Mains 2015 Forum › General Chemistry questions › C-10

A crystalline solid in which X atoms are located at the cube corners of the unit cell, oxygen atoms are located at the cube edges and sodium atoms at the cube centre. The molecular formula of the compound will be

(a) NaXO3

(b) Na2XO3

(d) NaXO4

#Chemistry #General Chemistry

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5 Answers

TANAY ·2010-04-14 10:21:41

ans is a?

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govind ·2010-04-14 10:22:23

Ans shud be A..
contribution by corner cells = 1/8 so total atoms = 1
contribution by edges = 1/4 so total atoms = 3

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Pritish Chakraborty ·2010-04-14 10:25:20

Contribution of X = 1/8 x 8 = 1 (8 corners)
Contribution of oxygen = 1/4 x 12 = 3(edges)
Contribution of sodium = 1 (centre)

Hence X : O : Na = 1 : 3 : 1

Hence formula is NaXO₃.

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UTTARA ·2010-04-14 10:30:11

Ya right but ans given D (in BT)

I agree with A

Thanks everyone

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Pritish Chakraborty ·2010-04-14 10:47:51

Ans would be (D) if there were 16 edges of cube..lol...each edge contributes 1/4th and there are only 12 edges of cube.

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C-10

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