Chemical Thermodynamics Problem

Determine the enthalpy change for the following reaction at 25°C:
C3H8(g) + H2(g) → C2H6(g) + CH4(g)

Using the Standard Heats Of Combustion that are given below....

The Standard heat of formation of C3H8(g) is -103.8 kJ / mol..

........................Ans: ΔH= -55.7 kJ.

Plz help !

4 Answers

30
Ashish Kothari ·

C3H8 → 3C + 4H2 ΔHf = 103.8 kJ/mol

3C + 3O2 → 3CO2 ΔHf = 3*(-393.5)=-1180.5kJ/mol

4H2 + 2O2 → 4H2O ΔHf = 4*(-285.8)=-1143.2kJ/mol

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C3H8 + 3C + 4H2 + 5O2 → 3C + 4H2 + 3CO2 + 4H2O ΔH = -2219.9 kJ/mol

H2 + 1/2O2 → H2O ΔH= -285.8 kJ/mol

2CO2 + 3H2O → 7/2O2 + C2H6 ΔH= 1560 kJ/mol

CO2 + 2H2O → 2O2 + CH4 ΔH = 890 kJ/mol

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C3H8(g) + H2(g) → C2H6(g) + CH4(g) ΔH = -55.7 kJ/mol

1
Abhisek ·

Thanks a lot for the solution ! :)

30
Ashish Kothari ·

Dont say thanks yaar.. You post questions which help us too.. So feel free! :)

1
Gurtej Singh ·

Simple HESS LAW.....

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