1i'l agree with Tapas regarding q1.
due to the smallest are of cross section of the upper part of vessel in A and the largest in C,the rise in height of the fluid will be greatest in A followed by C followed by B.
thus pA>pC>pB>pi
Question 1
MY ANSWER: C
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Question 2
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7 Answers
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29Ans 1 ...according to the conservation of mass..if the volume of a liquid expands so it's density shud dcrease..so i go with B
1FOR THE 1st questoni feel it B....
in all containers...when volume wl increase...then maximum increase in height will be in A>C>B......so pressure is increasing maximum for A>C>B............
so we r left with option B and C....
now pressure is h d g= h (m/V)*g=gm/(Î r2)
hence p i =p c
hence i feel the answer is B
106In Q1. there are two factors
(i) decrease in density
(ii) increase in height
now, density decreases uniformly for all substances whereas height increases max for case I, and min. in case II
As In case III, it is perfectly vertical walls, so increase in height and decrease in density perfectly cancel each other.
hence (B)
Q2. refracting angle of prism = 1/180 rad... << 1
therefore, the beam deviates by δ = (μ-1)A = 1/360 rad or 1°
so, considering the triangle made by image, prinicpal axis and optical center,
tan1° ≈ 1/360 rad = h/f
=> h = f/360 = 1/6
and as it is formed below the principal axis,
so h = -1/6 cm
1q1> i had thought on similar lines but for constant mass, volume increases because density decreases (as analogous in PV=nRT; pressure volume).
if not;
for any rise in temp (util 1+γΛt holds) there will be no change in height and hence, no pressure change, u mean (those with B). i found this quite absurd?
however, ans given is B and similar justification is provided.
still not satisfied.