466principle of conservation of momentum is required here
i.e., initial momentum = final momentum
A cannon ball is fired with a velocity v is an direction making an angle θ with the horizontal. At the highest point of its path it breaks into 2 parts of equal masses.One of the parts retraces the initial path of the ball.The speed of the second part immediately after explosion in m/s will be
a)32vcosθ
b)√32vcosθ
c) 2vcosθ
d) 3vcosθ
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3 Answers
1161Initial momentum of the body just before explosion will be mv cosθ
According to Conservation of Linear momentum:
Initial Momentum = Final Momentum (If external force is zero)
so, mv cosθ = -(m2)vcosθ+(m2)x (- sign because velocity get reversed)
Which will give you x = 3v cosθ
466principle of conservation of momentum is required here
i.e., initial momentum = final momentum
466