Just a second...

Which of the following aqueous solution of cation (s) gives (s) white ppt.

with NaOH and 4 NH OH solution and

formed ppt. is/are further completely dissolved in one of the excess reagent

a) Cd2+

b) Cr3+

c) Sn2+

 d) Bi3+

6 Answers

1
Avinav Prakash ·

i think the ans =a,b,c,d.plz discuss

4
UTTARA ·

I dont have the ans for this

Plzzzzzzzzzzzzzz

I request anyone to confirm the ans

[159]

13
Avik ·

Cr(OH)3 is green....so ruled out at the very 1st sight.

Rest of them form, White Insoluble Hydroxides (in water).

Sn(OH)2 dissolves in excess NaOH to form stannite ion, It also dissolves in excess NH3 sol.n.

Cd(OH)2 dissolves in excess Ammonia to from [Cd(NH3)4]2+.

Bi(OH)2 is a white ppt. but does not dissolve in either of the two reagents.

Hence, the answers are- (a),(c).

13
Avik ·

Reminds me of one more thing, not frm the Qn, but of the same genre...

Pb(OH)2 is also white & insoluble in water. It does not dissolve in excess NH4OH, but dissolves in excess NaOH.

1
pratik anand ·

Brillianntly dn avik. (C) is a correct option. (A) dissolves in excess NH4OH but in NaOH.......as avik said. So, w.r.t. to NaOH (a) nd (c) r crrect, bt w.r.t to NH4OH only (c)is correct......

4
UTTARA ·

Thanks Avik & Pratik

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