A dog of mass m is standing on the edge of a stationary horizontal turntable of totational inertia I and radius R. The dog walks once around the circumference of the turntable.
What fraction of a full circle does the dog's motion make with respect to the ground? Express your answer in terms of m, I and R. Ignore friction at the axle of the turntable.
We can conserve the angular momentum to get-
mvR = I(omega) where v is the velocity of dog w.r.t ground and omega is the angular velocity of the turntable w.r.t ground
No idea after this.
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UP 0 DOWN 0 0 2
2 Answers
62about the hinge.. or the center of the table..
the force by the dog on the table = force by table on dog (opposite in direction)
so the torque is equal... but opposite in direction
so I1α1 = -I2α2
integrating we get I1ω1=-I2ω2 (constant of integration will be zero because initally they were at rest..
Integrating again, we get I1θ1=-I2θ2
we know that θ1+θ2= 2pi
now solve [1]
