BASICS ROTATIONAL

JEE Advanced Questions › Mechanics questions › BASICS ROTATIONAL

a rod of weight, w is supportd by two parallel knife edges A and B and is in equilibrium in a horizontal position. the knives are at a distance of d from each other. the centre of mass of the rod is at a distance x from A. the normal reaction on A is ........ ??

and on B is............ ?

#Physics #Mechanics

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4 Answers

11

Mani Pal Singh ·2009-03-29 12:01:09

now equate the torque about the center of mass and resolve the forces in the vertical direction to get ur answer

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1

Kalyan Pilla ·2009-03-29 12:10:57

Equating forces
N₁+N₂=W

Equating Torques about A

Wx=N₂d

=>N₂=Wx/d

So N₁=W[1- (x/d)]
Normal reaction on A is W[1- (x/d)]

And on B is Wx/d

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questions ·2009-03-29 12:30:41

yeah exactly but the answer what BT depicts is

on A its w(d-x)

and on B its wx

guys !!

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Kalyan Pilla ·2009-03-29 12:36:45

That means there is no ~/d term there.
Jus' check if w is density[7][7][333]

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