996n1=mg
n2=mv2/r
fk=.3(n1+n2)
=.3m(g+v2/r)
a=-fk/m=.3(g+v2/r)
vds/dt=-.3(g+v2/r)
∫ds=-∫vdv/.3(g+v2/r) (from v0to 0)
I think u will get displacement(s) after integrating it
Ashutosh Gour swarna you have a good mind and approach but you made certain errors. The force will be resultant of g and v^2/r so root over is missing. Also in the second last line it should be v dv/ds instead of v ds/dt.Upvote·0· Reply ·2015-01-06 13:12:44