1you r welcome, dude!![1]
but why am i not getting the pink????????????????????? [16][16]
1)actually this ques is a tatoo ques :P::D ....i just wanted to confirm my answer thts why possting
draw fbd
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19 Answers
11\texttt{by pythagoras theorem} \\ \left (\frac{(b-x_1)}{2} \right )^2=d^2+x_2^2\\ \texttt{now u have a constraint binding} \ x_1 \ and \ x_2 \\ \texttt{so u can find} \ \frac{d^2x_2}{dt^2}\texttt{ in terms of } \frac{d^2x_1}{dt^2}\\ \texttt{now write laws of motion equations on both the masses}\\ m_1g-T=m_1\frac{d^2x_1}{dt^2}\\ 2T\cos\theta-m_2g=-m_2\frac{d^2x_2}{dt^2}\\ \texttt{eliminate T and find } \frac{d^2x_1}{dt^2}\\ \texttt{once u get all these u can easily find the P.E and K.E of the individual masses as a function of }x_1\\ \texttt{the system is stable if}\frac{d^2U}{dx_1}(at / x_1 \texttt{in equilibrium point })>0
1then what does pinking REALLY mean????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
1Is my soln to ques no.2 wrng??? I thought pink posts sort of confirm if the soln is right or wrong.why didnt i get pinked??(I'M NOT AFTER THE PINK!!)...
23@ akhil , i m b4 the pink [3] [3]
for Q 3 i m not sure but i think there isnt much in it
2Tcosθ=m2g, T=m1g
so cosθ=m22m1= x2(b-x1)/2
and [(b-x1)/2 ] 2 + x12=d2
so we can get x2 in terms of m1,m2,b,d
1actually mods r a lil busy dese dayss thtss why u not getting pink ....bhaii questions solve karo pink ki chinta mat karo...:P:D
12)
After rebound, the body has only horizontal velocity and hence no vertical velocity.
OA=H - h
t1=√2(H-h)/g
t2=time to reach from A to B= time to reach from A to B1=√2h/g
total time from O to B=t1+t2
=√2/g(√H-h+√h)
if t depends on h(H and g are constants), then max value of t= dt/dh=0
=d/dh{(H-h)1/2+h1/2}=0
or, h/H=1/2 .....(answer)
I WANT A PINK!!!!
12)a body freely falling from a giben height H hits an inclined plane in its path at a height h .as a result of this impact the direction of velocity of the body becomes horizontal .for what values of h/H the body will take maximum time to reach the ground??????
nd wht abt the minimum?????????
13)Consider the system of pulleys, masses, and string shown in the following figure. A light string of length b is attached at point A , passes over a pulley at point B located a distance 2d away, and finally attaches to mass . Another pulley with mass attached passes over the string, pulling it down between A and B . Calculated the distance x1 when the system is in equilibrium, and determine whether the equilibrium is stable or unstable. The pulleys are massless.....
my 2nd doubt is not yet cleared-post no.5
12)a body freely falling from a giben height H hits an inclined plane in its path at a height h .as a result of this impact the direction of velocity of the body becomes horizontal .for what values of h/H the body will take maximum time to reach the ground??????
nd wht abt the minimum?????????
