Find the force

IIT JEE 2015 Coaching › Mechanics questions › Find the force

A uniform rod of mass m and length l rests on a smooth horizontal surface.One of the ends of the rod is struck in horizontal direction at right angles to the rod.As a result the rod attains a velocity v.Find the force with which one half of the rod will act on the other in process of motion

#Physics #Mechanics

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

eureka123 ·2008-12-23 10:35:22

help

UP 0 DOWN 0
Post on FacebookPost anonymously?

Prashant Shekhar ·2008-12-23 14:35:06

Try to imagine what would happen if the rod breaks at the middle during the course of motion. This should be enough to get you the answer.
But probably you would need more information in order to calculate the rotational motion of the rod (since v and Ï‰ are not inter-related here).

UP 0 DOWN 0
Post on FacebookPost anonymously?

Prashant Shekhar ·2008-12-23 14:37:52

I am assuming v is the velocity of the centre of mass of the rod.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Lokesh Verma ·2008-12-23 20:13:17

let the impulse be R

R=mv

also, R.L/2=mL²/12.Ï‰

mvL/2=mL²/12 x Ï‰

Ï‰ = 6v/L

now we know the motion of the whole rod and of each part of the rod!

Draw the FBD of each part and you should get the answer by torque!

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Find the force

4 Answers

Your Answer

Add Image

Similar Questions