33Hey Eureka u are a bit confused..
Both are same... if u consider pressure.. then don't need to consider gravity...
Is the force applied by container same in both the cases... both containing liquid of same density Ï
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35 Answers
331IF HIEGHT IS SAME,
OBVIOUSLY 'M' IN 2ND CASE WILL B MORE HENCE THE CONTAINER WILL EXERT MORE FORCE ON FLOOR IN 2ND CASE
21force apllied will b diff in both cases.... had read da same que sumwer!!!!
i'll try 2 get da explntn soon...
1ahishek the first one seems ok....
greater the area at which force is acting, greater the force ....
incase the pressure is the same !!
btw, where did u get this question from ??.... what have they intended as the answer ?
at first look FII > FI
24oh yes...............I AM A BIG FOOL...............i was talking only about pressure force..........Didnt consider gravity..............F2>F1
sorry for wasting ur time with my bakwaas/.//
24are bhai jab pressure dono case mein same aur area bhi same ......to force kyun diff???????????????
1ONE SIMPLE ANSWER FOR THE ABOVE LONG DISCUSSION
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suppose u r asked to carry one of the contaIner on ur head ,then which 1 u will
carry?
(everything in both the container is same except the shape(hence the mass of liquid))
the answer would simply b the 1st one.
:)
1and hence in this question i will b "2nd container exerts more force on the floor'
1ya makgenius at first look it seems so . but .. the area of the base is same na in both cases .... so ..its ok to say same force is being acted !
1no its not ok
because the bend part of the frustum will exert some upward force
;
and this force it will take from floor;
;
ya the liquid force will b same in both the cases;
but the additional force by this bend(i.e. curved)part in case2;
(see the bend part is ultimately getting the force from floor only
)
are yaar sabse aaccha mere upar wale sawal ka jabab dedo sab khatm....kyun!!
11eureka i want the formula i dont remember im asking to check whether the volumes will be equal
11how will u find the volume of the frustum in case II
can some one post the formula
3abi the volume of the liquids in both thecontainer were the same
V=1/3∩h((2R)2-R2)h=∩R2h
and so P=F/A
which is same for bothe the cases
24Force is same in both(if external pressure is same in both)..........Shape of container doesnt matter.......it is the level of fluid which matters and the external pressure...........
24I told u yaar.............volume doesnt matter..........its the depth of fluid and the point at which u want to calculate pressure..............Since A and A' at same level so same force
33I got two explanations and not both can be correct..
Plz reply..
1)
drawing FBD of container... If V is vol of liquid in II case and πR2h is volume in case I
then VÏg=NII
and πR2h=NI
clearly NII>NI
2)
Pressure at A and A' is same that is Ïgh
so area at base = Ïgh*Ï€R2h.. same in both cases..
Which is correct.. [7]
33so you say...
if you place this on balance it will read zero..
24i will give u an example with which ur doubt should be clear...
Pressure is same in both at pt A and A'