1
lubu
·2010-04-02 22:01:14
U are almost der.
look,sinθ=h/l where h=L/2
so sinθ=L/2l=1/2√(Ï0/Ï)
1
Bicchuram Aveek
·2010-04-02 23:27:34
GUYS YOU HAVE GONE WRONG !!!
THE PART OF ROD IMMERSED UNDER WATER IS NOT L/2 !!!
11
SANDIPAN CHAKRABORTY
·2010-04-02 23:27:46
ya dats where the problem....
u r telling
sin @ = h/l where h = L/2
but from where are you getting h=L/2...
(you are assuming h to be the height of water in the tank rite?? then how is that h = L/2 = dist of com from either end of the rod????)
(i've assumed these...
L = length of rod
l = length of rod inside water
from pt where rod touch the surface tank to where W acts is L/2
from pt where rod touch the surface tank to where B acts is l/2..)
[12]
1
Bicchuram Aveek
·2010-04-02 23:34:31
I'm posting the solution ri8 now,......I've done it
1
Bicchuram Aveek
·2010-04-02 23:40:27
Taking moments about pt. A (to eliminate this hell of Normal Reaction),
moment due to upthrust = moment due to weight as rod is in equilibrium
AL g Ï cosθ . L/2 = A x Ï0 g cosθ . x/2
so L2 . Ï = x2 . Ï0
so x = L √(ÏÏ0)
now take the triangle involving the part of submerged rod, the depth of the liquid and the base of the tank.
sinθ = (depth of the tank) / AB
or sinθ = (L/2) / x
so sinθ = √(Ï0/Ï)2
Ans A.
1
Bicchuram Aveek
·2010-04-02 23:43:52
Sorry for the mistake in spelling of LENGTH.
1
Bicchuram Aveek
·2010-04-04 02:01:04
Are GYROSCOPES In syllabus ????
1
Bicchuram Aveek
·2010-04-06 11:17:40
GYROSCOPES NOT IN SYLLABUS RIGHT ??
1
Bicchuram Aveek
·2010-04-18 00:32:43
ARRRRRRRRRRRRRRRRRRRRRRRRREEEEEEEEEEEEEEYYYYYYYYYYYYYYYYYYYYYYYYYYY
WHAT IDEAS ABOUT GYROSCOPES ???????????????????????
SSSSSSSYYYYYYYYYYLLLLLLLLLAAABUUUUUUUUUUUUUUUSSSS
mmmmmmaaaaaaiiiiiiinnnnnnn
hhhhaaaaiiiii ki nnnaaahhhhhiii ????????
49
Subhomoy Bakshi
·2010-04-18 16:58:41
hehe!! ab yeh gyroscope kya cheez hai???
49
Subhomoy Bakshi
·2010-04-18 16:59:34
aeroplane gauges mein hotey hai kya? used to keep the plane straight? i mean is it the tilt measurer???