Mechanics - Gravitational field

283

Sahil Jain ·2014-06-13 08:41:58

See the us assume the v₁ is in positive and v₂ is in negative direction. or vice versa.
g wil act down ward so it will change the in both particles.
after time t
V_a= V₁ - gt
V_b= -V₂ - gt
now their velocity are perpendicular to each other.
dot product is zero
V_a.V_b= 0

(V₁ - gt).(-V₂ - gt)=0
solving t=âˆšV₁V₂/g
the distance between then will be V_rel*t
= {V₁ - (-V₂)}âˆšV₁V₂/g
putting the values of v1 and v2 respectively
we get d = 14âˆš3 / g

.

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ARKADYUTI BANDYOPADHYAY Well,the answer is 2.5m,but since your answer is perfectly logical and the answer is NEARLY correct to the actual answer,I may as well consider YOUR solution and YOUR answer to be the correct one.
Upvote·0· Reply ·2014-06-13 20:48:03
Sahil Jain 14* 1.71 / 9.8 = 2.5 m
Upvote·0· Reply ·2014-06-13 22:38:48
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466

Himanshu Giria ·2014-06-13 08:01:20

14âˆš3g

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ARKADYUTI BANDYOPADHYAY Can you explain your answer?
Upvote·0· Reply ·2014-06-13 08:06:16
ARKADYUTI BANDYOPADHYAY I'm totally in the dark as to how you arrived at this equation.
Upvote·0· Reply ·2014-06-13 08:07:12
Himanshu Giria is it right ??
Upvote·0· Reply ·2014-06-13 08:21:40
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ARKADYUTI BANDYOPADHYAY ·2014-06-13 08:17:33

Please explain.

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187

Swastik Haldar ·2014-06-13 08:27:41

You have to use the concept that dot product of two perpendicular vectors is 0. assume that they will become perpendicular after time 't'. treat the point from where they are are projected be the origin. so,
(-v1i -gtj).(v2i - gtj) = 0
solve for t and then find the distance, you will get the answer.

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