262x=(t-3)2
diff. w.r.t. t,
v= 2(t-3)=0
or t=3;
substituting in first eqn,
x=0;
Displacement of a particle in one dimension under action of a constant force is related to time t by eq.
t=√x+3
where x is in m and t in sec.
a> Find the displacement of a particle when its velocity is 0.
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UP 0 DOWN 0 0 3
3 Answers
262
1:P
I had done one mistake I had done X=(t-3)-2.......
Silly mistake :P
OK!!!!thanx........