MECHANICS Question !!

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Q1)Two particles 'm₁' and 'm₂' are connected by a light elastic string of natural length 'l_o' and are placed on a smooth horizontal table with separation between m₁ and m₂ as l_o. m₂ is projected with a velocity 'v_o' along the table at right angles to the string. Show that the max length ' l ' of the string is given by: l² = [v_o²m₁m₂(l + l_o)]/[k(m₁+m₂)(l - l_o)] ,where 'k' is force const. of string.
Also describe the motion of i)the system(m₁ & m₂)
ii)the COM(centre of mass)

#Physics #Mechanics

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6 Answers

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Anirudh Narayanan ·2009-01-10 01:10:12

'k' is force const. of string? I thought force constants were for springs? Pls reply [7]

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rkrish ·2009-01-10 01:13:20

'k' is not spring const.It is the force const.

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Anirudh Narayanan ·2009-01-10 01:14:48

What does it mean? [7][7][7][7][7]

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rkrish ·2009-01-10 01:19:05

k = the force reqd. to cause unit elongation (i.e. 1 m) in the string!!
S.I. Unit : Nm^-1

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Anirudh Narayanan ·2009-01-10 01:25:14

K. THANX [1]

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rkrish ·2009-01-10 01:27:35

Do not mention!!! :P:P

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