66The tension T is T=\dfrac{m}{2\pi r}v^2
A chain of mass m and radius r placed on a smooth table revolving with speed v revolving about a vertical axis coinciding with symmetry axis of chain.Find tension in chain
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24i considered element and wrote tension on it..........is my approach rite?????
similar to derivation of wave speed on circular wire.....
66yes.. that approach will work..
the inwards (towards the center) force will be T\delta \theta (where \delta \theta is the angle subtended by the elementary mass). This will provide the necessary centripetal acceleration:
T\delta \theta = \dfrac{m}{2\pi}\delta \theta \dfrac{v^2}{r}
giving us the desired result.