one in gravitation

and thnx for d answer shreyan and abhi............... d threadkeepers love u for d gr8 reply...

Abhijeet, if the size of the object is small, then the center of mass won't be 2h/3. It will be 2R/3, won't it?[7]

see i just saw the question and posted the solution i thought was the simplest forgive me bcoz i don't think i can read through all those 7 pages
here is my soln.

let a₁ be the acc. of earth (mass M_e)
and a₂ be the acc. of the mass 2M_e

then using laws of gravitation and as h<<R
a₁=2GM_e/R² (rem h<<R)

a₂=GM_e/R²

a_relative=3GM_e/R²

h=1/2a_relativet²

now what is so complicated in this and btw where does C.O.M came in b/w
hope this explains it well

P.S. = g=GM/R²

philip thnx for ur reply.i never thought that this thread will go for 7 pages while posting this thread

sory guys for those who participated in this thread for wasting ur time.

ya man i will say thnx only wen i got cleared.thats my policy