Physics doubt 2

Gravel is dropped on to a conveyor belt at the rate of 0.5 kg/s.The extra force required to keep the belt moving at 2 /s is

a)1 N
b)2 N
c)4 N
d)5 N
e)10 N

Please explain the question and answer in detail clearly

5 Answers

1
Manmay kumar Mohanty ·

see here as weight is added at a rate dmdt
there is a thrust force generated in the reverse direction
so Fnet = F - Fthrust
since this force reduces velocity
so the same force wuld be required to keep the belt moving at 2 m/s

so force required is Fthrust = vdmdt = 2 x 0.5 = 1 N

1
buddyboyyash ·

@manmay

wat actually is the thrust force??...n how is it generated backward when the body is falling from top??....is it another name for pseudo force??

1
kshankar93 ·

yes the same doubt for me too
I can't understand ur explanation

1
Manmay kumar Mohanty ·

Problems related to variable mass can be solved following these steps :
1. Make a list of all forces acting on the main mass and apply them on it.
2. Aplly an additional thrust force \vec{F_{t}} on the mass, the magnitude of which is \left|\vec{v_{r}} \left(\pm \frac{dm}{dt} \right)\right| where vr is relative velocity i.e, velocity of mass gained or masses ejected relative to the main mass, and the direction of \vec{v_{r}} is given by the direction of \vec{v_{r}} in case of mass increasing and otherwise the direction of -\vec{v_{r}} if mass is decreasing .
3. Find net force on the mass and apply \vec{F_{net}} =m\frac{d\vec{v}}{dt} ( m = mass at particular instant )
4. Integrate it with proper limits to find velocity at any instant of time t

now in abv problem mass is increasing so direction is \vec{v_{r}}
hence Fnet = F - Fthrust
Fnet = F - \vec{F_{net}} =\vec{v_{r}}\frac{dm}{dt}

had it been decreasing
Fnet = F + \vec{F_{net}} =\vec{v_{r}}\frac{dm}{dt}

1
buddyboyyash ·

oh k...understood...btw how does ur post get pink??

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