Rotation 1


VA= 5 M/S downwards

VB=10M/S downwards find the velocity of C?

1 Answers

1
Rohan Ghosh ·

taking frame of reference to be at A
velocity of B w.r.t A= 5 m/s downwards
hence omega w.r.t A= 5/a
hence velocity of C in reference to A=
perpendicular to AC and = 5/a*(√2a)=5√2
but C also has a velocity downwards = 5
hence totl velocity = vector sum=(√102+52)

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