1xactly..I did it in the same way...find the ans...
9 Answers
1two points to remember:-
1) after collision, direction of linear vel changes
2) ................., direction of angular velocity is same. [as wall is smooth]
62intially v=ωr
after colission , v=-v, ω=ω
friction is μR
a=μg
Torque = μmgr=2/5mr2α
thus, 5/2μg=αr
ω(t)=ω-αt=ω- 5/(2r) μgt
v(t)=-v+μgt
-v+μgt=ωr- 5/2μgt
7/2μgt=2v
μgt=4/7v
thus at pure rolling veloctiy is
3/7v
33oh!! u posted...
:)
but conserving angular momentum is more easy...
1intially v=ωr
i too took this ...
but suddenly am feeling... its not told so in the question.....[12]
can we take it?
1of course we can take it...... it is told that it is rolling initially...in the first few words ..