Rotational Mech

Show that If a rod is held at an angle θ to the horizontal and released, its lower end will not slip if friction b/w rod and ground is greater than
(3sinθcosθ)/(1+3sin2θ).

(...DC Pandey)

12 Answers

62
Lokesh Verma ·

this is not a very difficult problem...

Does not slip means we know something about that point...

also, we know N>=0

i think that should suffice...

I must confess, havent written down and solved it with pen and paper..... give it a shot!

62
Lokesh Verma ·

the right answer should by

(3sinθcosθ)/(1+3sin2θ)

Just tried solving it.. i think u missed the square of 2...

basically nto such an easy problem either...

had to spend 15-20 mins :(

33
Abhishek Priyam ·

Yeah thats square.

62
Lokesh Verma ·

u want the solution?

33
Abhishek Priyam ·

NO that was 4 others not U... I solved it.

62
Lokesh Verma ·

okie :)

62
Lokesh Verma ·

u got any clue to the n points problem?

33
Abhishek Priyam ·

I want soln of this question...

Q. A rod of length l forming an angle θ with horizontal strikes a frictionless floor at one of its end with center of mass velocity V0 and no angular velocity the impact was elastic. Find angular velocity of rod just after collision?

62
Lokesh Verma ·

see we need three equations...

1) energy balance...

2) impulse will cause a change of linear momentum

3) impulse will cause a change of angular momentum

33
Abhishek Priyam ·

Found my pink post ;)

1
voldy ·

I did'nt understand what you meant by " no angular velocity " ? please elaborate

62
Lokesh Verma ·

It means that it was falling vertically without any rotation!!

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