24
eureka123
·2009-02-28 09:20:17
figure clear nahin hai bhai....[2]
21
tapanmast Vora
·2009-02-28 09:27:11
isse clear nahi aata hai bhai!!! LOL... lagta che jeet gaya to tum gum mein duub gaye......
optn A : hor line : L max : mg/k above hor. line
optn A : hor line : L max : 2mg/k above hor. line
optn A : hor line : L + Mg/K max : mg/k above hor. line
optn A : hor line : L + Mg/K max : 2mg/k above hor. line
24
eureka123
·2009-02-28 09:31:24
amplitude par equilibrium condition hogi
=> kA=mg =>A=mg/k
ab kuch solve hua???????
21
tapanmast Vora
·2009-02-28 09:32:57
nahi gimme the ans.... acc to ur xplanation i guesss ans wud be A rite???
but A is not da Ans.
This que is frm tiit PART TEST 3
1
Terminator
·2009-02-28 09:42:03
[1][1][1][1][1]..........
3
nihit.desai
·2009-02-28 09:42:23
well, initially, is the spring at equilibrium position or is it at its natural length ??
21
tapanmast Vora
·2009-02-28 09:43:18
THIS IS WAT DA SOLTN READS :
27 (c) z = (L + mg/k) - (mg/k)cos(ωt)
3
nihit.desai
·2009-02-28 09:46:12
ya dats wat...so at t=0, Z shud be equal to L not L + mg/K...dats y i told B....
bcoz its equilibrium pos is L + mg/k..thn a SHM of ampl mg/k....
21
tapanmast Vora
·2009-02-28 09:51:24
YAH! ME 2 THOT SAME, so do u xpect a que like dis 2 cum or it shud hav bn more specific rite!
3
nihit.desai
·2009-02-28 09:54:07
dunno for sure dude...the concept of da que isnt wrng but jus da grphs in the options...m not too sure...nwys, i got to finish sum mac...so u carry on...
21
tapanmast Vora
·2009-02-28 09:55:24
ha ha... k k... "thou mayst take thy leave" LOL.... macbeth's ghost haunts me
1
Terminator
·2009-02-28 09:57:34
[9][9][9][9][9].....im [7][7][7][7].........