1Agreeing wid the title...
isko toh karna padega..
a standing wave existsi n a string of length 150cm fixed at both ends.THe displacement amplitude of a point at a distance 10cm from one of the ends is 10√3 mm.The distance b.w two nearest points within the same loop having smae displacement amplitude is 5√3 is 10mm
Q1 find max displacement amplitude of particle in string
Q2 mode of vibration of string(i.e overtone)
Q3 At what max distance from one end is potential energy of strign zero ??
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4 Answers
1''The distance b.w two nearest points within the same loop having smae displacement amplitude is 5√3 is 10mm''
dinn get this statement...
1I think it should have been "the distance between two nearest points within the same loop having same displacement amplitude of 5√3 is 10 mm "
