4I = IO e-μx
In qs
I/8 = I e-μ{ 36 x 10-3}
=> μ = 50
I/2 = I e-μ x
1/2 = e-50 x
=> x = 0.0138 m = 13.8 mm
The intensity of gamma radiation from a given source is I. On passing through 36 mm of lead, it is reduced to I/8. The thickness of lead which will reduce the intensity to I/2 will be ?
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3 Answers
44@Bhargav : Plzz verify the ans (I'm not sure abt the calculation part)
39Intensity of gamma radiation follows
i=I e^-ux
where I=original intensity
i=intensity after penetration through x
log I/i=ux
acc to the ques
(log 8)/(log2)=36/x=3
x=12mm