AIEEE 09 dbts


Q52. how to differentiate between (1) and (4) .. they have not stated which direction to take positive axis

Q43. yeh kya hai? (i mean i know logic gates.. but what are those dotted and solid lines in input?

21 Answers

62
Lokesh Verma ·

dotted lines are the time intervals.... (I mean generally one signal)

106
Asish Mahapatra ·

yes sir,,, the comprehension was from physics...

and I too feel taht the answer should be negative....

REASON:

In phy... work done by gas in expansion is positive
work done in compression by gas --- negative
work done on gas in expansion ----- negative
work done on gas in compression ---- positive

reason for these statements

In phy W = F.dx

in expansion F.dx > 0 ,F = F of gas .. so work done by gas > 0
in expansion F.dx < 0 , F=F(ext) .. so, work done on gas < 0
In compression F.dx < 0, F = F of gas .. so work done by gas < 0
In compression, F.dx > 0, F = F(ext). .. So work done on gas > 0

hope im correct in these statements..

1357
Manish Shankar ·

Sign Conventions are too confusing

If you go by physics, work done by system is taken as positive.
So according to that the answer in q 34 should be negative

106
Asish Mahapatra ·

thanks sir

btw ....

why is no one trying to even think about what I have written about the signs of the compre. question..... I know what we assume in chem AS WELL AS what we assume in phy ..regarding signs...

I am just asking ppl to read the question a bit more carefully and answer accordingly giving full justifiable answers...

1357
Manish Shankar ·

For (52)

In option (4) If I differentiate second graph(y vs t) it gives me the first graph(v vs t)

Regarding direction:

It is clear from second graph that y is decreasing, so +ve axis is taken upward

1
Sridhar M ·

read the ncert text book for physics...explanation is given how to solve the problems related to signals.

1
Manmay kumar Mohanty ·

-ve in expansion for chemistry thermo not physics thermo isliye ...

106
Asish Mahapatra ·

yeah yeah... my mistake..

1
Manmay kumar Mohanty ·

@ Asish i thnk lyman corresponds to ultraviolet .
how u said infrared culd be achieved with 2→1 transisition ??

1
Jagaran Chowdhury ·

52)@ashish observe carefully in (1) the graph comes down straight at t1,3t1. so it is wrong as it cannot have two velocities at the same time.

in (4) the graph is slightly tilted at those points making it correct.

it is nothing abt direction.that way both shud hav been correct

106
Asish Mahapatra ·

k sir... thanks

btw can u tell abt the signs of that phy comprehension question ? 34-36 ?

1
Manmay kumar Mohanty ·

43) is easy just write the truth table which is as
A B Output
0 0 0
0 1 0
1 0 0
1 1 1

now according to this graph is (2)
solid lines are as to the down states 0 output only inflexion in (2) shows 1 output.
that's wat i thnk but ya it's not clear though.

abt the 52) one not sure . so sry for that

62
Lokesh Verma ·

dotted lines are the time intervals.... (I mean generally one signal)

106
Asish Mahapatra ·

52. still unsure abt direction
43. solved yeah could be
55.. solved@mkm .. i know that logic..(even acc to that we still dont have guarantee that delta E will be low enough to give infrared waves)

but dont we get infrared for lyman series?? so shouldnt(2) be the answer also (assuming that (1) is correct)

84. im asking abt delta V...

as V = 600m/s ± 0.005%

Shouldnt delta V = 2*0.005%*600 m/s (as total variation is this much?)

34 work ON the gas (as it is expansion) is -ve naa?
35 work ON the gas (as it is compression) is +ve naa?

1
Avinav Prakash ·

52.> I THINK IT SHUD BE (4)

AS THE BALL IS FALLIN IT SHUD HAV -VE INITIAL VELOCITY

@MKM..IF I FOLLOOW UR METHOD IN Q43 THEN ..I AM GETTIN (B) AS ANS

39
Pritish Chakraborty ·

Manmay as long as his tables say they ain't wrong, they ain't wrong :P

1
Manmay kumar Mohanty ·

@asish don't u thnk there was a mistake in that chemistry Ionic radius wala question in AIEEE 2009[11]

1
Manmay kumar Mohanty ·

34)
Process A - B → pressure is constant
so W = PΔV → nRΔT → 2 x R ( 500 - 300 ) = 400 R

35)
D - A → temperature is constant
so W = 2.303 nRT log (VAVD) → 2.303 nRT log (PDPA) → 2.303 x 2 x R x 300 log 1052 x 105
→ - 1381.8R log 2 = - 415.92R ≈ -414 R according to option nearest

36)
W net = W A-B + WB-C + WC-D + W D-A
W CD = nRΔT= - 400 R
W BC = 2.303 nRT log (PBPC) = 693.2R

hence Wnet = 400R + 693.2 R - 400R - 414 R = 279.2R ≈ 276 R according to options

1
sanchit ·

i think 52) A.

1
Manmay kumar Mohanty ·

84)
Δx . ΔV = h4πm
→ Δx . 600 x 0.005100 = 6.62 x 10-344 x 3.14 x 9.1 x 10-31
→ Δx = 1.92 x 10-3 m

1
Manmay kumar Mohanty ·

55 ) for infrared wavelength shuld be low hence ΔE shuld be more which is for 5→4 transition i guess

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