Challenge for profs,olympiad guys and jee Qualified guys

Is it possible to construct a continuous and differentiable curve in the cartesian plane such that both the co- ordinates can never be simultaneously rational ?

take 0 < x,y <1

9 Answers

62
Lokesh Verma ·

I think no..

And i think this can be done by the fact that the no of rationals is countably infinite while irrationals is uncountably infinite

9
Celestine preetham ·

hmm i jus observed a function that satisfies this !

9
Celestine preetham ·

ans

xn+yn =1

where n≥3 ,ε N

it follows from fermats last thm

1
rickde ·

Fermat's Last Theorem states that no three positive integers a, b, and c can satisfy the equation an + bn = cn for any integer value of n greater than two.
but there can be rational numbers satisfying it

so this function can be simultaneously both co-od rational

9
Celestine preetham ·

rickde see #4 carefully again

x=a/c

y=b/c

1
rickde ·

let a,b,c be three rational numbers satisfying a^n+b^n=c^n n>3

so X=a/c so x is rational
similarly y is rational

so we have two rational numbers possible

11
Devil ·

@ rickdie, this is what Celestine wants...
x=ab
y=cd

(ad)n+(bc)n=(bd)n....Get it now?

1
rickde ·

got it

1
adroit ·

http://www.mathlinks.ro/viewtopic.php?t=299788

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