IN A TRIANGLE ABC, ALTITUDE FROM C ON AB AT F MEASURES 8 UNITS AND AB EQUALS 6 UNITS.
IF M AND P ARE THE MID POINTS OF AF AND BC. FIND THE LENGTH OF PM.
11
the answer is 5 cm..
Refer to the image..
Draw a line parallel to CF from M..
Therefore K is the midpoint of AC...
Draw a line parallel to AB from point P..it will also meet at K..
Now consider the triangle KPM
where KP is 3cm..(1/2 of AB)(From midpoint theorem)
KM=4cm(1/2 of CF)(From midpoint theorem)
Therefore PM=√32+42
=5..
36good solution.....
the other way is apply apollonius theorem in triangle CMB
nd substitute each lengths in terms of k where k = AM = FM
the terms gets cancelled nd we get PM = 5 units