INMO Geom...

It is not of this year...

ABc is a triangle with AB=AC...D is the mid-point of BC, P is any other point on AD. PE is perpendicular to AC.
\frac{AP}{PD}=\frac{BP}{PE}=\lambda \\ \ \frac{BD}{AD}=m\\ \ z=m^2(1+\lambda)\\ \text {Prove} \\ \boxed{z^2-(\lambda^3-\lambda^2-2)z+1=0}

1 Answers

11
Devil ·

None....no geometry-lovers?

Your Answer

Close [X]