13OK, me going with - a,b.
Multi-correct.
Q) In a prism of angle A and refractive index \mu, the maximum deviation occurs when -
a) Angle of incidence is 90 deg.
b) Angle of incidence is sin^{-1}\left(\left\{\sqrt{\mu^2-1} \right\}sinA-cosA \right)
c) Angle of emergence is sin^{-1}\left( \mu sin\left(A-\theta_c \right)\right)
d) Angle of emergence=angle of incidence.
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10 Answers
1a and c
δmax=90+i2-A
r1=θc
r2=A-θc
μ sinr2 = sin i2
i2=sin-1[μsin(A-θc)]
13Fr option b)....
\mu =\frac{Sin(i)}{Sin(r_1)} => Sin(r_1)=\frac{1}{\mu} \\ \\ Also, \mu=\frac{Sin(e)}{Sinr_2}\\ \\ Sin(e) = \mu.Sin(A-r_1) = Sin(A).\sqrt{{\mu}^2-1} -Cos(A)
1PAIR ANGLE OF INCIDENCE PUCH RAHA HAI THODI NA ANGLE OF EMERGENCE
13Arrey yaar, i-e are always in pair....agar "emergence" pe light incident karoge, toh "900" pe bahar aayegi, Deviation toh same hoga...!!
Incidence-Emergence angles can be interchanged, the path covered will be the same....
(Just like fr Snell's law formula, it really dosen't matter which angle is incidence n which one is angle of refraction, kahin se bhi bhejo path toh wohi hoga.)
