I DOUBT THE SOLUTION PROVIDED!~!

15 Answers

21
tapanmast Vora ·

PL. POST ur ans. here

1
ANKIT MAHATO ·

solving it yaar ...

21
tapanmast Vora ·

Any1 trying ?? [7]

1
voldy ·

after entering from the slab it should go along the other side.

21
tapanmast Vora ·

ya so we'll b using this : δm = 2i - A

r1 = r2 = A/2 =30°

sini = μsinr

NOW MY DBT IS WAT WILL U TAKE AS μ

**√3/2 or √2

11
Mani Pal Singh ·

bhai μ hamesha 1 se bada hi to lete hai na [1][1][1]

so wats the point in asking[7]

21
tapanmast Vora ·

Typo tha Janam samjha karo!! [6]

1
ANKIT MAHATO ·

30° ... ∂ = 2i - 60 , i = 45° since r is A / 2 = 30°
yaar the slab only displaces the ray .. does not change the angle of incidence ... u could keep the slab at a negligible distance from the prism .. then u could figure it out urself .. yaar ..

1
voldy ·

no this is where the mistake lies I think , here the ray is entering from the √3 slab , and not from air . check out my picture

21
tapanmast Vora ·

Yeah!!! Sri I m in full support wid u!!!

That was precisely y i posted it........

but then I was not sure.........

The solution says wat ankit says in : post #9

1357
Manish Shankar ·

Ankit is correct here

sini=μ1sine1=μ2sinr1=μ2sinr2=sine

21
tapanmast Vora ·

ummmm [12]

1
voldy ·

how's that possible ??? yahhan to √3 slab se light is going to prism na ??? [5][5][5][12][12] how please reasons needed . aap mughe dara rahe ho . please manish kyun aisa hota hai batiyenge plz ?

1357
Manish Shankar ·

srinath your diagram is not for minimum deviation

it looks like for maximum deviation

1
ANKIT MAHATO ·

srinath u have calculated the angle of deviation for grazing incidence ... this is not same as angle of min. deviation !!

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