MOD PHY (easy) : HELPPPPPP

calculate the min wavelength of X-rays emitted by an x-ray tube operating at a tube potential of 40KV??

9 Answers

1
madeforiit ·

I guess the fol. formula is 2 b used....
eV0 = hc/λmin
but then wat do v take as e as its not an electron its X-rays..

1
skygirl ·

arey it is electon only!

the electrons come out of the filament ...

travels through the accelerating voltage Vo ..

gets accelerated ... (acc = Ee/m = Vo . e/md)

and then strikes the target! .. from where X-rays come out...

so wat we do exactly is :

equate the energy ...

dat is : energy of the e- = energy of the emiitted photons.

actually whole energy is not used by the photons to come out.

but in case whole energy is used, we get the minimum wavelength.

1
skygirl ·

aman! kabhi toh apna doubts chcek karlo!

1
raamprasad ·

hey, can we use √(150/V) ? if i use dis,i get the answer as 0.0612372435696 A°

1
KR ·

min λ=1.227nm/√V
λ=1.227/√40000

λ=1.227/200 nm
~6.1pm

1
skygirl ·

wat are these ??

i mean i jus know one formula that madeforiit wrote in his 2nd post...

1
KR ·

λ=h/p---------1

and
p2 /2m =K.E=eV-----------2

p=√2meV

frm 1 and 2
λ=h/√2meV

for an electron h/√2me=1.227*10-9

1
raamprasad ·

hey wat i did was De-Broglie wavelength for an electron (in A°)

1
skygirl ·

oh haan yeh cheez pata tha mereko... but his question was something else...

mereko neend ara ... isiliye ni dikhra :( [13]

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