Wave Optics

IIT JEE 2015 Discussion Forum › Optics questions › Wave Optics

A screen is placed at a certain distance from a narrow slit which is illuminated by a parallel beam of monochromatic light of wavelength Î».
if d is the width of the slit,what is the angular width of the central maximum?

(a)sin^-1(Î»/d)
(b)2sin^-1(Î»/d)
(c)sin^-1(2Î»/d)
(d)sin^-1(Î»/2d)

#Physics #Optics

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7 Answers

1

sparkle2009 ·2008-12-16 00:52:08

please answer

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1

varun ·2008-12-16 00:54:06

c

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sparkle2009 ·2008-12-16 21:32:28

explain.

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Abhishek Priyam ·2008-12-25 03:45:36

I think this is a straight forward question....

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1357

Manish Shankar ·2008-12-25 03:59:12

This is single slit difraction pattern
The first minima occurs at path difference of Î»

sinÎ¸=Î¸=Î»/d

angular width is sinÎ±=sin2Î¸=2Î¸=2Î»/d

Î±=sin^-1(2Î»/d)

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sparkle2009 ·2008-12-25 05:04:36

I am sorry to break this to you all, the correct answer is (b)

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1357

Manish Shankar ·2008-12-25 06:12:28

Sorry...I made a mistake by assuming 2Î¸ to be very small

sinÎ¸=Î»/d

so Î±=2Î¸

Î±=2sin^-1(Î»/d)

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Your Answer

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω