Combo Pack -II

Ans 3 : Total number of monochlorination products = 3(without including stereochem) and 4 with stereochem

Ans 4 : B
Fe is in +1 oxidation state in this compound..and the configuration is 4s¹3d⁶..so the config will be 3d⁷ as one electron shifts from 4s to 3d wen the orbitals are hybridised..
3d⁷ so no chances of pairing..C ruled out..and it will have 3 unpaired electrons so D is also incorrect..

And EAN of this compound does not depend on the charge of NO...that's wat i think..btw NO donates three electrons in this case unlike all ligands that donate two electrons..

3) Yes, thts right govind...maine galati se galat answer dekh liya tha.

4) Ans's right; But why dosen't EAN depend upon NO's charge...?
Moreover, i didn't know NO donates 3-electrons here,,,Phir "Fe" ka Coordination no. kya hoga ??

Qn(s) 1 & 3 left too...

Okay, rest done....

To Finish off 3),
The answer is- IV>I>II>III .
Why is II>III...?

No Attempts ? :(