11I think ans is D.
cyclopropane(3 membered ring) is more strained(Baeyer strain theory) than cyclobutane(4 membered).
1-3 dibromopropane ---->(Zn + Δ) A ------> (HBr) B ------> (alc. KOH) C ----------> (Br2) D ---------> (alc. KOH/NaNH2) E
identify A,B,C,D,E
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11
1the last one is your bicyclic compound . not the other one .
b/w one Q
St.A : cyclopropane is formed more easily than cyclobutane
StB : the energy of activation for formation of cyclobutane is more
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106ok..
another one...
1-bromo, 3-chloro cyclobutane --->(Na/ether) ?
11For any terminal alkyne
R--C ≡ CH ---NaNH2----> R--C ≡ C - --- + R' + (from R'Br )----> R--C ≡ C--R'
11CH3--CH2--CH2--OH + H2SO4(conc.) ---> CH3--CH=CH2
----NBS----> CH2(Br)--CH=CH2 ---aq.KOH or noist Ag2O----> CH2(OH)--CH=CH2
11If 2 moles are not mentiond , then there are 2 diff. alkenes possible .
11In 1st Q.
2 moles of acetaldehyde shud be mentiond.
So final pdt has 7 C's (conjugated diene)
2nd is also a conj.diene.
11bhaiyya......
no. of C's in 1st ans are 1 less.[1]Also H missing(But its understood).
1er....rkrish I think u r wrong,,,,the Br shud b at the 3rd carbon....(allyl)
11NBS reaction proceeds via free radical.
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--c=c--c-- + NBS ---> -c=c-- c --
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Br
62name the alkene which on reductive ozonlysis gives the following products:
(i) acetaldehyde + 2-oxo propanal 
(ii) acetone + glyoxal + formaldehyde
1)
2) 
106convert
(i) propyl alcohol to allyl alcohol (CH2=CH-CH2-OH)
(ii) ethyne to propyne
106name the alkene which on reductive ozonlysis gives the following products:
(i) acetaldehyde + 2-oxo propanal
(ii) acetone + glyoxal + formaldehyde
1see the important part to notice here is that the reaction is kinetically controlled and not thermodynamically .
the formation of cyclohexane is thermodynamically preferred but the afifinity for Br for Zn is high hence it abstracts th Br nearby and leaves as ZnBr2 .
hence cyclopropane is formed