INTEGER ANSWER TYPE 4

Ans 4 ...
see (NH₄)₂S reduces one of the NO₂ grps to NH₂ then 2 Br attack at the ortho position of that NH₂ grp....NaNO₂ / HCl forms diazonium salt..Sn/Hcl reduces the nitro grp to NH₂ then again Br attacks at the ortho position of NH₂ ....see in this question temp is not mentioned so i am not sure whether N₂Cl will be removed or not...if it's removed it creates a possibility that Br attacks at it's position but since the ring will be highly deactivated due to the presence of 4 Br grps so i dont think another Br will attack..so ans shud be 4 only

@Govind Ans is 5

@Govind Can u draw E plzzzzzzzzzzzz?

So that it ill be easy to understand