INTEGER ANSWER TYPE 5

1) How many number of possible condensation products are obtained when proponal and propanone are together treated with moderately concentrated alkali ?

10 Answers

39
Pritish Chakraborty ·

3? just a guess.

4
UTTARA ·

Ans given is 4

39
Pritish Chakraborty ·

Propanal mein toh ek hi carbanion ban sakta hai na? Even I was thinking 4 at first...I didn't try by writing down.

4
UTTARA ·

What r those 4

i was getting only 2 ????????????/

39
Pritish Chakraborty ·

Wait propanone mein bhi ek hi carbanion possible hai...lol symmetrically same both sides.
See, 2 carbanions means 4 products. A carbanion can react with its initial substrate or with another substrate.

4
UTTARA ·

Can u name the products plzz

I am unable to understand

39
Pritish Chakraborty ·

Naming them will take a while...kaam karo, aldol condensation ke mechanism se karo. CH3CH-CHO and CH2-COCH3 are possible carbanions. Make each of them react by nucleophilic addition on propanal and propanone one by one. So 4 products will be possible. One carbanion can add to either propanal or propanone.

4
UTTARA ·

Fine Pritish Thx I'll try to get the products

Plzz confirm them whenever u r free

4
UTTARA ·

2 oxo hex3ene

2methyl4oxopen2ene

2,3dimethyl4oxobutane

1oxo2methylpent2ene

Thanks Govind

29
govind ·

1. Hex-3-en-2-one
2. 3 methyl pent-2-en-1-al
3. 4 methyl pent-3-en-2-one
4. 2,3 dimethyl but-2-en-1-al

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